Solve the system of equations using the addition method 2a+3b=-1 ; 3a+5b=-2

Answer:Then, a=-1 and b=-1Step-by-step explanation:We need to solve the following system of equations using the adition method:2a+3b=-1       (i)3a+5b=-2      (ii)First, we multiply the equation (i) by -3 and the equation (ii) by 2, so we get:-6a-9b=36a+10b=-4Adding the two equations we have:-6a-9b=36a+10b=-4--------------------------  0  + b = -1Then b=-1. Now, let's substitute the value of b into equation (i):2a+3b=-12a + 3(-1) = -12a -3 = -12a = 2a = 1Then, a=-1 and b=-1