a) P(Z <-1.26)b) P(Z > 1.48)c) P(1.44 < Z<2.79)

Answer:a) P (Z < - 1.26) = 0.60383b) P (Z > 1.48) = 0.56944c) P (1.44 < Z < 2.79) = 0.07229Explanation:You need to use a table with the cumulative normal standard distribution, which shows the areas for different values of Z-scores.I attached part of the table for the cumulative probability that  gives the probability that a statistic is between 0 (the mean) and Z.a) P (Z < - 1.26)The table shows the probabilities for positive values of Z. Since the normal distribution is symmetric P (Z < - 1.26) = P (Z > 1.26).Also, note that you will find the probability for Z ≤ 1.26, so the probability that you want is P (Z > 1.26) = 1 - P(Z ≤ 1.26)From the table: P (Z ≤ 1.26) is 0.39617.Then, P (Z > 1.26) = 1 - 0.39617 = 0.60383.As said, P (Z < - 1.26) = P (Z > 1.26), so it is 0.60383.b) P (Z > 1.48)P (Z > 1.48) = 1 - P( Z ≤ 1.48)From the table, P (Z < 1.48) = 0.43056P (Z > 1.48) = 1 - 0.43056 = 0.56944c) P (1.44 < Z < 2.79)P (1.44 < Z < 2.79) = P (Z < 2.79) - P (Z < 1.44) From the table: P (Z < 2.79) = 0.49736, and P (Z < 1.44) = 0.42507P (Z < 2.79) - P( Z < 1.44) = 0.49736 - 0.42507 = 0.07229